Problem :-
"A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable." — Wikipedia: String (computer science)
This exercise is to test your understanding of Java Strings. A sample String declaration:
String myString = "Hello World!"
The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.
Given two strings of lowercase English letters, and , perform the following operations:
- Sum the lengths of and .
- Determine if is lexicographically larger than (i.e.: does come before in the dictionary?).
- Capitalize the first letter in and and print them on a single line, separated by a space.
Input Format
The first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.
Output Format
There are three lines of output:
For the first line, sum the lengths of and .
For the second line, write Yes
if is lexicographically greater than otherwise print No
instead.
For the third line, capitalize the first letter in both and and print them on a single line, separated by a space.
Sample Input 0
hello
java
Sample Output 0
9
No
Hello Java
Explanation 0
String is "hello" and is "java".
has a length of , and has a length of ; the sum of their lengths is .
When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore, is not greater than and the answer is No
.
When you capitalize the first letter of both and and then print them separated by a space, you get "Hello Java".
Solution :-
//Code By Sumit Teli ( Rank 1 In Java)import java.io.*;import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner sc=new Scanner(System.in); String A=sc.next(); String B=sc.next(); System.out.println(A.length() + B.length()); if (A.compareTo(B) > 0) { System.out.println("Yes"); } else { System.out.println("No"); } A = A.substring(0, 1).toUpperCase() + A.substring(1); B = B.substring(0, 1).toUpperCase() + B.substring(1); System.out.println(A + " " + B); }}