Java If-Else - Hacker Rank Solution - GitHub -Tutoriallpoints  

Problem :-

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: 
 is odd and odd numbers are weird, so we print Weird.

Sample Case 1: 
 and  is even, so it isn't weird. Thus, we print Not Weird.

Solution :-

//Code By Sumit Teli ( Rank 1 In Java)

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {

        /* Read input */

        Scanner scan = new Scanner(System.in);

        int n = scan.nextInt();

        scan.close();

        

        /* Determine answer */

        String ans = "";

        if (n % 2 == 1) {

            ans = "Weird";

        } else {

            if (n >= 6 && n <= 20) {

                ans = "Weird";

            } else {

                ans = "Not Weird";

            }

        }

        

        /* Print output */

        System.out.println(ans);

    }

}